برنامه بررسی بخش‌پذیری دو عدد

num1= int(input())
num2 = int(input())

def barresi(num1, num2):
if num2 == 0 :
print("What? 0 akhe mashti")
elif num1 % num2 == 0:
print(f"{num1} Bakhsh Pazire Bar {num2}")
else:
print(f"{num1} Bakhsh Pazir Bar {num2} nist")

print(barresi(num1, num2))

#include<iostream>
    using namespace std;
    int main(){
int x ,y;
cin>>x>>y;
if (y!=0  && x%y ==0) {cout<<"yes";}
else{ cout<<"no";}
return 0;}

def check(a:float,b:float,/) -> str:
        if b==0:
            print(f"The division is not defined !!!by zero")

        elif a % b==0:
            print(f"They can be divided!!")
        else:
            print(f"They can't be divided!!")

num1 = int(input("enter your number1 ="))
num2 = int(input("enter your number 2 ="))

if num1 % num2 == 0:
    print("num1 bar num2 bakhshpazir mibashad")
else:
    print("num1 bar num2 bakhshpazir nemibashad")

def divisibility(x,y):
    if y==0:
        return "Error"
    if x%y==0:
        return f"{x} is divisible by {y}"
    return f"{x} isn't divisible by {y}"

a=int(input("x: "))
b=int(input("y: "))
print(divisibility(a,b))

#Rashid
while True:
    def get_numbers():
        user_input = input("Please enter your numbers: ")

        cleaned_input = user_input.replace(',', ' ')

        str_list = cleaned_input.split()

        numbers = []
        for item in str_list:

            if item.replace('.', '', 1).isdigit(): 
                if '.' in item:
                    numbers.append(float(item))
                else:
                    numbers.append(int(item))
            else:
                print("Please enter a valid number.")
                return None


        return numbers

    numbers = get_numbers()

    if numbers is not None:

        if len(numbers) != 2:
            print("Please enter two numbers, not more. ")
        else:
                if numbers[0] % numbers[1] == 0:
                    print("the first number is feasible on the second digit.")
                else: 
                    print("the first number isn't feasible on the second number. ")
                break