یافتن ایندکس دوم یک عنصر در لیست Python

list1 = ['a' , 'b' , 'c' , 'd' ]
print(len(list1))
#dige bar asase tedade chiz hayi ke tooye list hast:
#b  =  dovomin index hastesh

def last_index(list,character):
    length=len(list)-1
    while length!=-1:
        if character==list[length]:
            return length
        length-=1
    return length
list1 = ["a","b","c","b"]
print(last_index(list1,"b")) #output:3

list1 = ["a", "b", "c", "b"]

for i,j in enumerate(list1, start=1):
    if i == 2:
        print(f"{i}: {j}")
    else:
        continue

list1 = ["a", "b", "c", "b"]
a=0
for i,d in enumerate(list1):
    if d == "b":
        a+=1
    if a==2:
        print(i)
        break

list1.1
حتما ۱ باشه چون اعداد تو پایتون از ۰ شروع میشن

list=["a","b","c","d","b","f"]
l2=[]
for i,l in enumerate(list):
    if l=="b":
        l2.append(i)
print(max(l2))

my_list = ["a", "b", "c", "d", "e"]
print(my_list[1])