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همهٔ تمرین‌ها

تبدیل عدد به باینری (صفر و یک)

تمرین آسان 2548 visibility link download flag

تابعی بنویسید که یک عدد را به باینری یا یک رشته باینری را به عدد تبدیل کند

👨‍💻 14 ساعت قبل کاربر ناشناس این تمرین رو مشاهده کرد

پاسخ‌ها 19

#include <iostream>
#include <cmath>
using namespace std;
int q(long int x , string y){
    long int b ,a;
    int i ,c = 1 ,n ,s ,d = 1 ,e = 1 ,j;
    b = 0;
    s = 0;
    a = x;
    for (n = 1 ; a / 10 > 0 ; n++){
        a = a / 10;
    }
    if (y == "b"){
        for (x ; x > 0 ; x = x / 2){
            b = b + (x % 2) * c;
            c = c * 10;
        }
        return b;
    }
    else if (y == "o"){
        for (i = 0 ; i < n ; i++){

            s = s + ((x / d) % 10) * e;
            d = 10;
            e = 2;
            for (j = 0 ; j < i ; j++){
                d = d * 10;
                e = e * 2;
            }
        }
        return s;
    }
    else{
        cout<<"eror!!! : we have only binery and number !!!";
        cin>>x;
        cin>>y;
        q(x , y);
    }
}
int main(){
    long int x;
    string y;
    cout<<"enter the number : ";
    cin>>x;
    cout<<"would you like it to be binary {b} or Ordinary number {o} : ";
    cin>>y;
    cout<<q(x ,y);
    return 0;
}
Aref.2 C & C++ 
n=int(input("Enter your number:"))
bi=''
while n>0:
    bi=str(n%2)+bi
    n=n//2
print('binary:',bi)
User 2785 Python 
def binary():
    output = 0
    status = input('''
    1. convert int to bin
    2. convert bin to int
    please choice:
    ''')
    if status == '1':
        inputing = int(input('enter the value:'))
        output = bin(inputing)[2:]
    elif status == '2':
        inputing = input('enter the bin num:')
        output = int(inputing, base=2)
    else:
        output = 'not currect. please try again'
        print(output)
        return binary()

    print(output)

binary()
Sajjad.alishahy1382 Python 
def binary(number):
    if type(number) == int:
        if number < 0:
            return "The entered number is not positive."
        else:
            answer = ""
            if number == 0:
                answer = "0"
            else:
                while number > 0:
                    remainder = number % 2
                    answer = str(remainder) + answer
                    number = number // 2
            return answer
    elif type(number) == str:
        run = False
        for i in number:
            if i == "1" or i == "0":
                run = True
            else:
                return "This string is not binary."
        if run:
            result = 0
            for w in number:
                result = result * 2 + int(w)
            return result
        else:
            return "input is empty"
Amirabbas.jafarian Python 
#include <iostream>
#include <cmath>
using namespace std;
int main(){
	int x;
	cout << "Enter a number";
	cin >> x;
	cout << x << endl;
	int baghimande = 0;
	int bainery  = 0;
    for(int i = 0; x>0; i++){
    	int a;
		baghimande = (x/2);
	    a = x%2;
	    bainery += (a*pow(10,i));
	    x = baghimande;
	}
	cout << bainery;
}
User 2720 C & C++

Py

def bin(n) :
    binary = ""
    while n > 1 :
        if n == 3 :
            binary += "11"
        elif n == 2 :
            binary += "01"
        else :
            binary += str(n%2)
        n = n//2
    print(binary[::-1])

while True :
    n = int(input("Enter a number = "))
    if n==0 :
        print(0)
    elif n==1 :
        print(1)
    else :
        bin(n)
Sedvaghefi Python 
a=input("choose: 1.Convert a number in base ten to binary  2.Convert the number in binary form to base 10\n")
if a=="1":
    b=int(input("Enter a number in base ten : \n"))
    l=[]
    j=b
    while True:
        c=j%2
        d=j//2
        l.append(c)
        if d>=2:
            j=d
            continue
        else:
            l.append(d)
            break
    k=len(l)
    print("Number in binary form = ",end="")
    while k>0:
        print(l[k-1],end="")
        k-=1
if a=="2":
    r=input("Enter the number in binary form : \n")
    y=[]
    t=len(r)
    while t>0:
        y.append(r[t-1])
        t-=1
    m=0
    for i,j in enumerate(y):
       m+=int(j)*(2**i)
    print("Number in base 10 =",m)
Zaras Python 
def f(n):
    if n==0:
        return '0'
    m=''
    while n>0:
        m+=str(n%2)
        n=n//2
    return m
n=int(input(":"))
print(f(n ))
Yega18neh85 Python 
x = int(input("Enter integer number: "))

lst = []
while x>0:
    c = x%2
    x = x//2
    lst.append(c)

st = ""
for i in lst[::-1]:
     st += str(i)

print(f"binery number is {st}")
Najme.s.y Python 
import time
start_time = time.time()
class Binary:
    def __init__(self,number):
        self.number = number

    def click_number(self):
        bins = bin(self.number)
        return bins

while True:
        num = int(input("enter your number ="))
        print(Binary(num).click_number())
        if num == 0:
            print("end while")
            break
Sumy.amiri Python

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